Class 9 Motion Science Study Notes

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Class 9 Motion Study Notes

We come across thousands of moving things on a daily basis. How are these moving objects different from one another? Class 9 Motion chapter describes this in detail. In this blog, you get to learn about Class 9 motion in a simple yet convenient language. Learn everything starting from the definition of motion, to its types, solved examples and question answers with these exclusive notes!

What is Motion? 

If the position of an object varies over time, the object is considered to be in motion:

Motion on the Straight Line 

Distance – The distance covered by the object is defined as the complete length of the path covered by the object between the two endpoints. 

Distance

Distance is a numeric number. We may not specify the direction in which the object moves when mentioning the distance travelled by the object. The distance in Physics is the length of the direction (line or curve) defined by an object travelling through space. The distance is independent of the course. Thus, certain physical quantities that do not need guidance for their full definition are called scalars. When a body moves from one position to another, the shortest distance between the body’s original and final position, along with its path, is known as displacement. 

Displacement

Displacement has both orientation and magnitude for its full definition, and thus these physical quantities are called Vectors. The distance travelled by a moving body cannot be zero, but the final displacement of a moving body may be Zero. 

Displacement is denoted by Δx
Δx = xf ​− x0
Where,
xf = Final position on the object
x0 = Initial position of the object

Must Read: Here are NCERT Class 9 Science Solutions!

Difference Between Distance and Displacement

Distance Displacement 
Distance provides the complete details of the path taken by the object  Displacement does not  provide the complete details of the path taken by the object
Distance is always positive  Displacement can be positive, negative or zero 
It is a scalar quantity  It is a vector quantity
The distance between two points may not be unique  Displacement between two points is always unique 

Uniform vs Non-Uniform Motion

If the body covers equal lengths in equal time intervals, so it is assumed to have a Uniform Motion. If the body covers unequal distances at equal intervals or equal distances at unequal intervals, so the body is said to have Non-uniform Motion.

Speed

Speed is defined as the total distance travelled by the object in the time interval during which the motion takes place. SI unit of speed is meter per second. 

Speed = Distance Travelled / Time Taken

Velocity

Velocity of a body is known as the rate of change of displacement of a body with the passage of time. Velocity of a moving object is measured in meters per second in SI units. 

Acceleration

Acceleration is a measure of the change in the velocity of an object per unit time. SI unit of acceleration is ms-2. The equation can mathematically be written as:

Accelaration

Uniform Acceleration

The body is said to have a uniform acceleration if it is going on a straight path and the velocity shifts (increases or decreases) by equal proportions at equal time intervals. 

No-Uniform Acceleration

A body is said to have a non-uniform acceleration if the velocity shifts (increases or decreases) by unequal proportions at unequal time frames.

Graphical Representation of Motion

Distance – Time Graphs

Distance – Time Graphs represents a change in position of the object with respect to time. The graph in case the object is stationary (means the distance is constant at all time intervals) – Straight line graph parallel to x = axis

For a body at rest, as the slope is zero, so speed of the body is zero

class 9 Motion

For a body moving with uniform speed

class 9 Motion

For accelerated motion., the slope of graph is increasing with time

For decelerated (speeding down) motion., slope of graph is decreasing with time

class 9 Motion

Velocity- Time Graphs

Constant velocity is a straight line graph, velocity is always parallel to the x-axis. When a body is moving with a uniform velocity, the slope of AB indicates zero acceleration

When a body starts from rest and moves with uniform acceleration, then it is greater is the slope of v-t graph, greater will be the acceleration

When a body is moving with uniform acceleration and its initial velocity is not zero

When a body is moving with increasing acceleration, the slope gradually increases with time

When a body is moving with decreasing acceleration, the the slope decreases with time

When a body is moving with uniform retardation and its initial velocity is not zero, as θ > 90°, the graph has a negative slope

class 9 Motion

Equations of Motion

The equations of motion represent the relationship between an object’s acceleration, velocity and distance covered if and only if,

  • The object is moving on a straight path
  • The object has a uniform acceleration

Three Equations of Motion

Equation for Velocity – Time Relation
v = u + at

Equation for Position – Time Relation 
s = ut + 1/2 at2

Equation for the Position – Velocity Relation
2a s = v2 – u2

Where, 
u: initial velocity
a: uniform acceleration
t: time
v: final velocity
s: distance travelled in time t

Deriving the Equations of Motion

Deriving the Equation for Velocity – Time Relation

Acceleration = Change in velocity / time taken
Acceleration = (final velocity – initial velocity) / time
a = (v – u)/t
so, at = v – u
v = u + at

Deriving Equation for Position – Time Relation

We know that, distance travelled by an object = Area under the graph
So, Distance travelled = Area of OPNR = Area of rectangle OPQR + Area of triangle PQN
s = (OP * OR) + (PQ * QN) / 2
s = (u * t) + (t * (v – u) / 2)
s = ut + 1/2 at2           [because at = v – u]

Deriving the Equation for Position – Velocity Relation

We know that, distance travelled by an object = area under the graph
So, s = Area of OPNR = (Sum of parallel sides * height) / 2
 s = ((PO + NR)* PQ)/ 2 = ( (v+u) * t)/ 2
2s / (v+u) = t [equation 1]Also, we know that, (v – u)/ a = t [equation 2]On equating equations 1 and 2, we get,
2s / (v + u) = (v – u)/ a
2as = (v + u) (v – u) 
2 as = v2 – u2

Practice One-Word Questions on Class 9 Motion

1. __________________ is defined as the total distance traveled by the body in the time interval during which the motion takes place.
2. __________________ unit of speed is m/s
3. The ratio of total distance to total __________________ taken by the body gives its average speed.
4. The rate of change of displacement of an object with the passage of time is known as __________________ of the object.
5. velocity of a body is a vector quantity involving both distance and __________________. 

Answers

1.Speed
2. SI
3. time
4. Velocity
5. Displacement

These were class 9 Motion study notes! Hope you found answers to all your questions in this blog. Selecting the right stream after class 10th plays a great role in making a successful career. Reach out to Leverage Edu experts and make the right career choice! Book a FREE counselling session today!

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