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Simplification Questions for Bank Exam 🏦: Quantitative Aptitude

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Simplification Questions for Bank Exam

Simplification Questions for Bank Exams: The simplification topic covers a big portion in the Upcoming government exams of the Banking sector. If you are preparing to appear in the IBPS, SBI or any other banking exams, you should practice the simplification question well. It will boost your confidence and give you some tricks/hacks to solve the questions. Without delaying anymore, let’s have a look on Simplification Questions for Bank exams with answers.

20+ Simplification Questions for Bank Exam 📑 

Following are some questions that you can practice on Simplification for the banking exams.

Q1. Simplify the expression 12/3 + 5(2 – 1). 

Solution: 
We can simplify by first evaluating the expressions inside the parentheses: 12/3 + 5(2 – 1) = 4 + 5(1) Then, we can multiply and add: 5(1) = 5 4 + 5 = 9 Therefore, 12/3 + 5(2 – 1) simplifies to 9.

Q2. Simplify the expression 2(4 + 6) – 3(2 + 5). 

Solution: 
We can simplify by first evaluating the expressions inside the parentheses: 2(4 + 6) – 3(2 + 5) = 2(10) – 3(7) Then, we can multiply and subtract: 2(10) = 20 and 3(7) = 21 20 – 21 = -1 Therefore, 2(4 + 6) – 3(2 + 5) simplifies to -1.

Q3. Simplify the expression (3x – 7) + (2x + 5) 

Solution: 
Combine like terms: (3x – 7) + (2x + 5) = (3x + 2x) + (-7 + 5) = 5x – 2 Therefore, the simplified expression is 5x – 2.

Q4. Simplify the expression 2(3x + 4) – 5x + 2(2x – 3) 

Solution: 
Distribute the coefficients: 2(3x + 4) = 6x + 8 2(2x – 3) = 4x – 6 Combining like terms: 6x + 8 – 5x + 4x – 6 = (6x – 5x + 4x) + (8 – 6) = 5x + 2 Therefore, the simplified expression is 5x + 2.

Q5. Simplify the decimal 0.875.

Solution: 
Express the decimal as a fraction: 0.875 = 875/1000. Find the greatest common factor of 875 and 1000: 875 = 5 x 5 x 7 x 2 x 5 1000 = 2 x 2 x 5 x 5 x 5 The greatest common factor is 125. Divide both numerator and denominator by 125: 875/1000 = (875 ÷ 125)/(1000 ÷ 125) = 7/8. Therefore, the simplified decimal is 7/8.

Q6. Simplify the fraction (2/3)/(4/5).

Solution: 
Invert the denominator and multiply: (2/3)/(4/5) = (2/3) x (5/4) = 10/12. Reduce the fraction: 10/12 = (10 ÷ 2)/(12 ÷ 2) = 5/6. Therefore, the simplified fraction is 5/6.

Q7. Simplify the expression (2x + 3y)^2 – (2x – 3y)^2 

Solution: 
Using the difference of squares formula: (a^2 – b^2) = (a + b)(a – b) (2x + 3y)^2 – (2x – 3y)^2 = [(2x + 3y) + (2x – 3y)][(2x + 3y) – (2x – 3y)] = (4x)(6y) = 24xy Therefore, the simplified expression is 24xy.

Q8. Simplify: 5(2x + 3) – 2(3x – 1) + 4x

Solution: 
Distribute the coefficients and combine like terms: = 10x + 15 – 6x + 2 + 4x = 8x + 1.

Q9. Simplify: (3a – 2b)² – 4(a + b)²

Solution: 
First, square the terms inside the parentheses: = (9a² – 12ab + 4b²) – 4(a² + 2ab + b²) Distribute the negative sign: = 9a² – 12ab + 4b² – 4a² – 8ab – 4b² Combine like terms: = 5a² – 20ab

Q10. Simplify the fraction 3/4 + 1/6.

Solution: 
Find a common denominator: 3/4 + 1/6 = (3 x 3)/(4 x 3) + (1 x 2)/(6 x 2) = 9/12 + 2/12 = 11/12. Therefore, the simplified fraction is 11/12.

Also Read: How to Prepare for Bank Exams

Directions (11-20): What value should come in the place of (?) in the following questions.

Q11. √729 * 8 + ? = 8(2/3) * √1296

A.78
B.86
C.68
D.96
E.103
Solution: D
√729 * 8 + ? = 8(2/3) * √1296
216 + ? = 26/3 * 36
? = 96

O12. (155 ÷ 1665) * (74 ÷ 3100) * ? = 10

A.4500
B.4200
C.4800
D.5100
E.5300
Solution: A
(155 ÷ 1665) * (74 ÷ 3100) * ? = 10
? = 10 * 3100 * 1665/155 * 74
? = 4500

Q13. 35 * 26 + √3136 = ? * √529

A.35
B.45
C.39
D.42
E.25
Solution: A
(155 ÷ 1665) * (74 ÷ 3100) * ? = 10
? = 10 * 3100 * 1665/155 * 74
? = 4500

Q14. 80% of 750 + 40% of 1060 = ?2  

A.32
B.37
C.41
D.29
E.39
Solution: A
80% of 750 + 40% of 1060 = ?2
600 + 424 = ?2
? = 32

Q15. 1680 ÷ 8 + 1360 ÷ 16 = ? + 19 * 5

A.180
B.190
C.200
D.210
E.220
Solution: C
1680 ÷ 8 + 1360 ÷ 16 = ? + 19 * 5
210 + 85 = ? + 95
? = 200

Q16. 48 % of 325 + 115% of 140 = ?

A.312
B.298
C.308
D.317
E.327
Solution: D
48 % of 325 + 115% of 140 = ?
156 + 161 = ?
317 = ?

Q17. ? = 23 * √169 – √361 * 21

A.-100
B.-120
C.-140
D.-160
E.-180
Solution: A
? = 23 * √169 – √361 * 21
? = 299 – 399
? = -100

Q18. (66 ÷ 225) * (45 ÷ 528) * ? = 4

A.140
B.120
C.160
D.180
E.200
Solution: C
(66 ÷ 225) * (45 ÷ 528) * ? = 4
? = 160

Q19. (133 ÷ 7) – (145 ÷ 5) = ?

A.-14
B.-8
C.–15
D.–10
E.0
Solution: D
(133 ÷ 7) – (145 ÷ 5) = ?
19 – 29 = ?
? = -10

Q20. 40 % of 300 + 15 * 24 = ? + 275

A.205
B.210
C.220
D.225
E.240
Solution: A
40 % of 300 + 15 * 24 = ? + 275
120 + 360 = ? + 275
? = 205

📌 Importance of Simplification Questions

Check the given points of importance of the simplification questions:

  • The questions are to test the ability of the candidates to solve complex questions.
  • It arrives in most banking exams like SBI PO, RBI Grade B, NABARD GRADE A, and more.
  • These questions are easy to solve and carry most of the marks.

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FAQs

How do you solve simplification in bank exams?

You can use the BODMAS rule to solve these types of questions.

What are simplification questions?

Simplification questions will be asked in two ways, so you all have to know both types,

Is the bank exam easy to crack?

Yes, it is easy to crack but requires the right tips and tricks to be implemented.

What are the tips for solving simplification questions for bank exams?

1. Memorize table up to 20
2. Memorize squares and cubes up to 30.
3. Learn basic mental calculations.
4. Practice regularly
These are the basic tips and tricks to solve the simplification questions for banking exams.

This was all about the Simplification Questions for Bank Exam.  For more such informative blogs, check out our Banking Exams Section, or you can learn more about us by visiting our  Indian exams page.

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