Simplification Questions for Bank Exam 🏦: Quantitative Aptitude

Solution: 
We can simplify by first evaluating the expressions inside the parentheses: 12/3 + 5(2 – 1) = 4 + 5(1) Then, we can multiply and add: 5(1) = 5 4 + 5 = 9 Therefore, 12/3 + 5(2 – 1) simplifies to 9.

Solution: 
We can simplify by first evaluating the expressions inside the parentheses: 2(4 + 6) – 3(2 + 5) = 2(10) – 3(7) Then, we can multiply and subtract: 2(10) = 20 and 3(7) = 21 20 – 21 = -1 Therefore, 2(4 + 6) – 3(2 + 5) simplifies to -1.

Solution: 
Combine like terms: (3x – 7) + (2x + 5) = (3x + 2x) + (-7 + 5) = 5x – 2 Therefore, the simplified expression is 5x – 2.

Solution: 
Distribute the coefficients: 2(3x + 4) = 6x + 8 2(2x – 3) = 4x – 6 Combining like terms: 6x + 8 – 5x + 4x – 6 = (6x – 5x + 4x) + (8 – 6) = 5x + 2 Therefore, the simplified expression is 5x + 2.

Solution: 
Express the decimal as a fraction: 0.875 = 875/1000. Find the greatest common factor of 875 and 1000: 875 = 5 x 5 x 7 x 2 x 5 1000 = 2 x 2 x 5 x 5 x 5 The greatest common factor is 125. Divide both numerator and denominator by 125: 875/1000 = (875 ÷ 125)/(1000 ÷ 125) = 7/8. Therefore, the simplified decimal is 7/8.

Solution: 
Invert the denominator and multiply: (2/3)/(4/5) = (2/3) x (5/4) = 10/12. Reduce the fraction: 10/12 = (10 ÷ 2)/(12 ÷ 2) = 5/6. Therefore, the simplified fraction is 5/6.

Solution: 
Using the difference of squares formula: (a^2 – b^2) = (a + b)(a – b) (2x + 3y)^2 – (2x – 3y)^2 = [(2x + 3y) + (2x – 3y)][(2x + 3y) – (2x – 3y)] = (4x)(6y) = 24xy Therefore, the simplified expression is 24xy.

Solution: 
Distribute the coefficients and combine like terms: = 10x + 15 – 6x + 2 + 4x = 8x + 1.

Solution: 
First, square the terms inside the parentheses: = (9a² – 12ab + 4b²) – 4(a² + 2ab + b²) Distribute the negative sign: = 9a² – 12ab + 4b² – 4a² – 8ab – 4b² Combine like terms: = 5a² – 20ab

Solution: 
Find a common denominator: 3/4 + 1/6 = (3 x 3)/(4 x 3) + (1 x 2)/(6 x 2) = 9/12 + 2/12 = 11/12. Therefore, the simplified fraction is 11/12.

A.78
B.86
C.68
D.96
E.103
Solution: D
√729 * 8 + ? = 8(2/3) * √1296
216 + ? = 26/3 * 36
? = 96

A.4500
B.4200
C.4800
D.5100
E.5300
Solution: A
(155 ÷ 1665) * (74 ÷ 3100) * ? = 10
? = 10 * 3100 * 1665/155 * 74
? = 4500

A.35
B.45
C.39
D.42
E.25
Solution: A
(155 ÷ 1665) * (74 ÷ 3100) * ? = 10
? = 10 * 3100 * 1665/155 * 74
? = 4500

A.32
B.37
C.41
D.29
E.39
Solution: A
80% of 750 + 40% of 1060 = ?2
600 + 424 = ?2
? = 32

A.180
B.190
C.200
D.210
E.220
Solution: C
1680 ÷ 8 + 1360 ÷ 16 = ? + 19 * 5
210 + 85 = ? + 95
? = 200

A.312
B.298
C.308
D.317
E.327
Solution: D
48 % of 325 + 115% of 140 = ?
156 + 161 = ?
317 = ?

A.-100
B.-120
C.-140
D.-160
E.-180
Solution: A
? = 23 * √169 – √361 * 21
? = 299 – 399
? = -100

A.140
B.120
C.160
D.180
E.200
Solution: C
(66 ÷ 225) * (45 ÷ 528) * ? = 4
? = 160

A.-14
B.-8
C.–15
D.–10
E.0
Solution: D
(133 ÷ 7) – (145 ÷ 5) = ?
19 – 29 = ?
? = -10

A.205
B.210
C.220
D.225
E.240
Solution: A
40 % of 300 + 15 * 24 = ? + 275
120 + 360 = ? + 275
? = 205

You can use the BODMAS rule to solve these types of questions.

Simplification questions will be asked in two ways, so you all have to know both types,

Yes, it is easy to crack but requires the right tips and tricks to be implemented.

1. Memorize table up to 20
2. Memorize squares and cubes up to 30.
3. Learn basic mental calculations.
4. Practice regularly
These are the basic tips and tricks to solve the simplification questions for banking exams.