The largest 5-digit number that leaves a remainder of 5 when divided by both 8 and 9 is 99,941. To find the greatest number of 5 digits that will give a remainder of 5 when divided by 8 and 9 respectively we need to use the concept of LCM (Least Common Multiple, which is 72 in this case) to find a general form for the numbers that satisfy the given conditions (x = 72k + 5). Then, we will find the largest 5-digit number that fits this form.
Complete Answer:
Here is a step by step process to find the greatest number of 5 digits that will give a remainder of 5 when divided by 8 and 9 respectively
Step 1: Understanding the condition
Let the required number be N .
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When N is divided by 8, it leaves a remainder of 5.
Mathematically:This means is divisible by 8.
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Similarly, when is divided by 9, it leaves a remainder of 5.
Mathematically:This means is divisible by 9.
Hence, is a common multiple of 8 and 9.
Step 2: Finding the least common multiple (LCM) of 8 and 9
The LCM of 8 and 9 can be calculated as:
Thus, is a multiple of 72.
Let , where is a positive integer.
This gives:
N = 72 k + 5 N = 72k + 5
Step 3: Finding the greatest 5-digit number
The greatest 5-digit number is 99999.
We want .
Subtract 5 from both sides:
Now divide both sides by 72 to find :
Since must be an integer, take the greatest integer less than or equal to 1388.805:
Step 4: Calculate
Substitute into :
Step 5: Verify the solution
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Check if leaves a remainder of 5 when divided by 8:
This is correct.
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Check if leaves a remainder of 5 when divided by 9:
This is also correct.
Final Answer:
The greatest 5-digit number that leaves a remainder of 5 when divided by both 8 and 9 is: 99941
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