{"id":801954,"date":"2023-12-21T18:23:19","date_gmt":"2023-12-21T12:53:19","guid":{"rendered":"https:\/\/leverageedu.com\/discover\/?p=801954"},"modified":"2023-12-21T18:23:19","modified_gmt":"2023-12-21T12:53:19","slug":"exam-prep-boats-and-streams","status":"publish","type":"post","link":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/","title":{"rendered":"20 + Boats and Streams Questions and Answers | Quantitative Aptitude\u2b07\ufe0f\ud83d\udcdd"},"content":{"rendered":"\n<p>Boats and streams questions are the mathematical questions that come into various competitive exams like quantitative aptitude section of major government exams. To excel these questions in an examination, practicing them is the key. Here are some questions to help you practice and develop a group on them to ace the examination.<\/p>\n\n\n\n\n\n\n<h2 class=\"wp-block-heading\">Important Formulas\ud83d\udcdd<\/h2>\n\n\n\n<p>If the speed of a boat in still water is x km\/h and the speed of the stream is y km\/h, then&nbsp;<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Downstream speed (v) = (x + y) km\/h<\/li>\n\n\n\n<li>Upstream speed (u) = (x-y) km\/h<\/li>\n<\/ul>\n\n\n\n<p>From this relationship, we can say that&nbsp;<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Speed of Boat in still water = (u + v) \/ 2 km\/h<\/li>\n\n\n\n<li>Speed of Steam = (v &#8211; u) \/ 2 km\/h<\/li>\n<\/ul>\n\n\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-boats-and-streams-questions-and-answers\">Boats and Streams Questions and Answers \ud83d\udcdd<\/h2>\n\n\n\n<p>Below are the boats and streams questions with answers to help you practice them and ace at the examination.<\/p>\n\n\n\n<div class=\"schema-faq wp-block-yoast-faq-block\"><div class=\"schema-faq-section\" id=\"faq-question-1703146299641\"><strong class=\"schema-faq-question\">Q 1. A person can swim in water with a speed of 13 km\/hr in still water. If the speed of the stream is 4 km\/hr, what will be the time taken by the person to go 68 km downstream?<\/strong> <p class=\"schema-faq-answer\">2.5 hours   <br\/>3 hours   <br\/>4 hours   <br\/>3.5 hours   <br\/><span style=\"font-size: revert; color: initial;\">4.5 hours<\/span><br\/><br\/>Answer: (3) 4 hours<br\/>Solution:<br\/>Downstream Speed = (13+4) km\/hr = 17 km\/hr<br\/>To travel 68 km downstream.<br\/>Time taken = 68\/17 = 4 hours<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146357529\"><strong class=\"schema-faq-question\">Q 2. In one hour, a boat goes 13 km\/hr in the direction of the stream and 7 km\/hr against the direction of the stream. What will be the speed of the boat in still water?<\/strong> <p class=\"schema-faq-answer\"> 8 km\/hr   <br\/>10 km\/hr   <br\/>14 km\/hr   <br\/>6 km\/hr   <br\/>Cannot Be Determined  <br\/><br\/>Answer: (2) 10 km\/hr<br\/>Solution:<br\/>According to the formula,<br\/>Speed of a boat in still water = \u00bd (DownstreamSpeed + UpstreamSpeed)<br\/>Speed of boat in still water = \u00bd (13+7) = \u00bd \u00d7 20 = 10 km\/hr<br\/><\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146358577\"><strong class=\"schema-faq-question\">Q 3. A woman can row upstream at 16 km\/hr and downstream at 26 km\/hr. What is the speed of the stream?<\/strong> <p class=\"schema-faq-answer\">5 km\/hr<br\/>2 km\/hr<br\/>4.5 km\/hr<br\/>21 km\/hr<br\/><br\/>Answer: (1) 5km\/hr<br\/>Solution:<br\/>According to the formula,<br\/>Speed of the stream = \u00bd (Downstream Speed \u2013 Upstream Speed)<br\/>Speed of the stream = \u00bd (26-16) = \u00bd \u00d7 10 = 5 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146360843\"><strong class=\"schema-faq-question\">Q 4. A speedboat, whose speed in 15 km\/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. What is the speed of the stream in km\/hr?<\/strong> <p class=\"schema-faq-answer\">2.5 km\/hr   <br\/>3.5 km\/hr   <br\/>4 km\/hr   <br\/>5 km\/hr   <br\/>3.25 km\/hr  <br\/><br\/>Answer: (4) 5 km\/hr<br\/>Solution:<br\/>Let the speed of the stream be x km\/hr<br\/>Upstream Speed = 15 + x<br\/>Downstream Speed = 15 \u2013 x<br\/>So, {30 \/ (15+x)} + {30 \/ (15-x)} = 4 \u00bd (4 hours 30 minutes)<br\/>\u21d2 {900 \/ (225-x2)} = 9\/2<br\/>\u21d2 9x<sup>2<\/sup> = 225<br\/>\u21d2x<sup>2<\/sup> = 25<br\/>\u21d2x = 5<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146363047\"><strong class=\"schema-faq-question\">Q 5. A boat is moving 2 km against the current of the stream in 1 hour and moves 1 km in the direction of the current in 10 minutes. How long will it take the boat to go 5 km in stationary water?<\/strong> <p class=\"schema-faq-answer\">1 hr 20 minutes   <br\/>1 hr 30 minutes   <br\/>1 hr 15 minutes   <br\/>30 minutes   <br\/>45 minutes  <br\/><br\/>Answer: (3) 1 hr 15 minutes<br\/>Solution:\u00a0<br\/>Downstream = (1\/10 \u00d7 60) = 6 km\/hr<br\/>Upstream = 2 km\/hr<br\/>Speed in still water = \u00bd (6+2) = 4 km\/hr<br\/>So, the time is taken by the boat to go 5km in stationary water = 5\/4 hrs = 1 \u00bc hrs = 1 hr 15 minutes<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146811784\"><strong class=\"schema-faq-question\">Q 6. A boat takes 27 hrs to travel a distance upstream and takes 9hrs to travel the same distance downstream. If the speed of the boat in still water is 12km\/hr, then what is the velocity of the stream?<\/strong> <p class=\"schema-faq-answer\">4km\/hr<br\/>6km\/hr<br\/>8km\/hr<br\/>10km\/hr<br\/><br\/>Ans : B<br\/>Explanation: Let the velocity of the stream be y km\/hr<br\/>Then the speed of the downstream = (12 + y)km\/hr<br\/>The speed of the upstream = (12 \u2013 y)km\/hr<br\/>9 (12 + y) = 27 (12 \u2013 y)<br\/>108 + 9y = 324 \u2013 27y<br\/>27y + 9y = 324 &#8211; 108<br\/>36y = 216<br\/>y = 6 km\/hr\u00a0<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146812712\"><strong class=\"schema-faq-question\">Q 7. A boat covers 12 km upstream and 18km downstream in 3hrs while it covers 18 km upstream and 12km downstream in 3(1\/4) hrs the velocity of the the boat upstream and downstream?<\/strong> <p class=\"schema-faq-answer\">12km\/hr<br\/>14km\/hr<br\/>16km\/hr<br\/>18km\/hr<br\/><br\/>Ans : A<br\/>Explanation: Let rate of upstream be &#8216;x&#8217;km\/hr and downstream be &#8216;y&#8217; km\/hr<br\/>Then, 12\/x + 18\/y = 3 &#8211;>1<br\/>18\/x + 12\/y =13\/4 &#8211;>2<br\/>Adding 1 and 2 we get,<br\/>30\/x + 30\/y = 25\/4<br\/>1\/x + 1\/y +=5\/24 &#8211;>3<br\/>Subtracting 1 and 2 we get<br\/>1\/x \u2013 1\/y = 1\/24 &#8211;>4<br\/>Adding 3 and 4 we get,<br\/>2\/x = 6\/24 ; x= 8 ->5<br\/>Substitute 5 in 3 we get, y=12<br\/>Speed of upstream = 8 km\/hr and downstream = 12 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146813625\"><strong class=\"schema-faq-question\">Q 8. If a boy rows 8 km downstream in 6 hours and 4 km upstream in 4 hours then how long will he take to cover 16 km in stationary (still) water?<\/strong> <p class=\"schema-faq-answer\">8<br\/>14<br\/>22<br\/>16<br\/><br\/>Ans : B<br\/>Explanation: Distance covered in downstream = 8 km<br\/>Time taken in downstream = 6 hours.<br\/>Rate of downstream = 8\/6=4\/3 km\/hr<br\/>Distance covered in upstream = 4 km<br\/>Time taken in upstream = 4hours.<br\/>Rate of upstream = 4\/4 = 1 km\/hr<br\/>Speed in still water = (1\/2)(4\/3+1) = 7\/6km\/hr<br\/>Time Taken to cover 16 km in still water = 16*6\/7=14hrs (approximately)<br\/><\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146814572\"><strong class=\"schema-faq-question\">Q 9. A boat takes 24 hours to cover 128 km downstream and 16 hours to cover 64 km upstream. Then the speed of the boat in still water is:<\/strong> <p class=\"schema-faq-answer\">14\/3<br\/>8\/7<br\/>3\/2<br\/>9\/5<br\/><br\/>Explanation: Distance covered in downstream = 128km<br\/>Time taken in downstream = 24 hours.<br\/>Rate of downstream = distance \/ time = a = 128 km \/24 hours = 16\/3km\/hr<br\/>Distance covered in upstream = 64km<br\/>Time taken in upstream = 16 hours.<br\/>Rate of upstream = distance \/ time = b = 64km \/16hours = 4 km\/hr.<br\/>Speed in still water = (a + b) \/ 2 = (1\/2)(16\/3+4) km\/hr = (1\/2)(28\/3)km\/hr<br\/>= 14\/3km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703146815607\"><strong class=\"schema-faq-question\">Q 10. A pedal boat goes 12km upstream and 14km downstream in 3hrs. It goes 15km upstream and 10.5km downstream in 3 hrs 15mints. The speed of the boat in still water is:<\/strong> <p class=\"schema-faq-answer\">10<br\/>15<br\/>20<br\/>25<br\/><br\/>Ans : A<br\/>Explanation: Let &#8216;x&#8217; be the speed of the boat in still water<br\/>Let &#8216;y&#8217; be the speed of the current.<br\/>Pedal boat will travel downstream at (x + y)km\/hr and upstream (x \u2013 y)km\/hr<br\/>Therefore 14\/x +y + 12\/ x \u2013y = 3<br\/>10.5\/(x+y) + 15\/(x-y) = 13\/4<br\/>70\/(x+y) +60 \/(x-y) =15 &#8211;>1<br\/>42 \/(x+y) + 60\/(x-y) = 13 &#8211;>2<br\/>From 1 and we get,<br\/>x+y = 14 ; x-y = 6<br\/>Therefore x= 10 ; y = 4<br\/>The speed of the pedalboat is 10 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703147109660\"><strong class=\"schema-faq-question\">Q 11. A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mints to cover a distance of 10km upstream. Find the speed of the river current in km\/hr.<\/strong> <p class=\"schema-faq-answer\">1kmph<br\/>1.5kmph<br\/>2.0kmph<br\/>2.5kmph<br\/><br\/>Ans : B<br\/>Explanation: Rate downstream = 30 \/ (11\/2) km\/hr<br\/>= 30 * 2 \/ 11 km\/hr<br\/>= 60\/11 km\/hr<br\/>Rate upstream = 10 \/ (17\/4)km\/hr<br\/>= 10 * 4 \/ 17 km\/hr<br\/>= 40 \/ 17 km\/hr<br\/>Speed of current = 1 \/ 2 (a \u2013 b) km\/hr<br\/>=1 \/ 2 (60 \/ 11 \u2013 40 \/ 17)<br\/>= 1.5 km\/hr (approx.)<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703147110752\"><strong class=\"schema-faq-question\">Q 12. A man can row 4 km against the stream in 40mins and return in 36mins. Find the rate of current.<\/strong> <p class=\"schema-faq-answer\">1\/3kmph<br\/>2\/3kmph<br\/>4\/3kmph<br\/>5\/3kmph<br\/><br\/>Ans : A<br\/>Explanation: Speed of the man (upstream) = (4 \/ 40 * 60) km\/hr<br\/>= 6 km\/hr<br\/>Speed of the man (downstream) = ( 4 \/ 36 * 60) km\/hr<br\/>= (60 \/ 9)km\/hr<br\/>= 20\/3 km\/h<br\/>Rate of the current = \u00bd[downstream speed \u2013 upstream speed]<br\/>= (1\/2) [ 20 \/ 3 \u2013 6] km\/hr<br\/>Rate of the current = 1\/3 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703147111638\"><strong class=\"schema-faq-question\">Q 13. Sakthi rows a boat at 4 km upstream in 1hour and 1 km downstream in 20 minutes. How long will he take to reach 3.5km in still water?<\/strong> <p class=\"schema-faq-answer\">1<br\/>2<br\/>3<br\/>4<br\/><br\/>Ans : A<br\/>Explanation: Upstream Speed = 4\/1 = 4km\/hr<br\/>Downstream Speed = 1\/20 = 0.05 km\/min<br\/>= 0.05*60 = 3 km\/hr<br\/>Hence, speed of boat = 1\/2( Upstream Speed + Downstream Speed)<br\/>= 1\/2 (4+3)km\/hr =3.5 km\/hr<br\/>Thus, the time required to reach the distance of 3.5 km=DistanceCovered\/Speed of boat<br\/>= 3.5\/3.5km\/hr =1 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703147112748\"><strong class=\"schema-faq-question\">Q 14. A motor boat sails 30 km of a river towards upstream in 10hrs. How long will it take to cover the same distance downstream, if the speed of the current is \u00bd of the speed of the boat in still water.<\/strong> <p class=\"schema-faq-answer\">8hr<br\/>3.33hr<br\/>5hr<br\/>4.33hr<br\/><br\/>Ans : B<br\/>Explanation: Upstream speed = x \u2013y<br\/>Downstream speed = x + y<br\/>x\u2013 y = 30\/10 = 3km\/hr<br\/>Again x = 2y<br\/>Therefore x \u2013 y = 3<br\/>y= 3km\/hr ; x = 6km\/hr<br\/>Therefore x + y = 9 km\/hr<br\/>Time during downstream = 30\/9 = 3.33hrs<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703147113757\"><strong class=\"schema-faq-question\">Q 15. Vinny can row 15km\/h in still water and it takes twice as long to row up the stream than to row down. Find the rate of the stream.<\/strong> <p class=\"schema-faq-answer\">1.8 km\/hr<br\/>3.33 km\/hr<br\/>5 km\/hr<br\/>33 km\/hr<br\/>Solution- 5km\/h<br\/>The ratio between downstream and upstream speed = 2:1<br\/>Let the upstream speed be 2x, then the speed downstream will be x<br\/>Speed is still water = (v+u) \/ 2 = (2x + x) \/ 2 = 3x\/2 = 15 (given)<br\/>Hence, x = 10 km\/h<br\/>Speed of stream = (v-u)\/2 = (20-10)\/2 = 5 km\/h<br\/><\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161655933\"><strong class=\"schema-faq-question\">16. Mohana can row 80km upstream and 110km downstream in 26 hrs. Also she can 60km upstream and 88km downstream in 20 hrs. Find the speed of the girl in still water and the speed of the current in ratio:<\/strong> <p class=\"schema-faq-answer\">5:6<br\/>3:7<br\/>7:9<br\/>8:3<br\/><br\/>Ans : D<br\/>Explanation: Let rate upstream = &#8216;x&#8217; km\/hr and<br\/>Rate downstream = &#8216;y&#8217; km\/hr<br\/>Then 80\/x + 110\/y = 26 &#8212;>1<br\/>60\/x + 88\/y = 20&#8211;>2<br\/>By solving 1 and 2<br\/>y= 11 ; x = 5<br\/>Rain in still water = (1\/2) (11 + 5) km\/hr = 8 km\/hr<br\/>Rain of current = (1\/2) (11 \u2013 50) km\/hr = 3 km\/hr<br\/>The required answer is 8:3<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161657253\"><strong class=\"schema-faq-question\">17. A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?<\/strong> <p class=\"schema-faq-answer\">8:3<br\/>5:2<br\/>3:7<br\/>2:4<br\/><br\/>Ans : A<br\/>Explanation: Let the man&#8217;s rate upstream be &#8216;x&#8217; km\/hr and downstream be &#8216;y&#8217; km\/hr<br\/>Then distance covered upstream by 4hrs 24mints = distance covered by downstream in 2hrs<br\/>(x * 4 2\/5) = y *2<br\/>22x\/5 = 2y<br\/>Y = 11x\/5<br\/>Required ratio = (y+x\/2) : (y \u2013x\/2)<br\/>= 16x\/10 : 6x\/10<br\/>= 16x : 6x<br\/>= 8:3<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161660685\"><strong class=\"schema-faq-question\">18. A person can swim in water with a speed of 13 km\/hr in still water. If the speed of the stream is 4 km\/hr, what will be the time taken by the person to go 68 km downstream?<\/strong> <p class=\"schema-faq-answer\">1hr<br\/>2hr<br\/>3hr<br\/>4hr<br\/><br\/>Ans : D<br\/>Explanation: Downstream Speed = (13+4) km\/hr = 17 km\/hr<br\/>To travel 68 km downstream.<br\/>Time taken = 68\/17 = 4 hours<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161663243\"><strong class=\"schema-faq-question\">19. In one hour, a boat goes 13 km\/hr in the direction of the stream and 7 km\/hr against the direction of the stream. What will be the speed of the boat in still water?<\/strong> <p class=\"schema-faq-answer\">10km\/hr<br\/>20km\/hr<br\/>30km\/hr<br\/>40km\/hr<br\/>Ans : A<br\/>Explanation: According to the formula,<br\/>Speed of a boat in still water = (1\/2) (DownstreamSpeed + UpstreamSpeed)<br\/>Speed of boat in still water = (1\/2) (13+7) = (1\/2) \u00d7 20 = 10 km\/hr<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161664403\"><strong class=\"schema-faq-question\">20. A woman can row upstream at 16 km\/hr and downstream at 26 km\/hr. What is the speed of the stream?<\/strong> <p class=\"schema-faq-answer\">1km\/hr<br\/>5km\/hr<br\/>3km\/hr<br\/>9km\/hr<br\/><br\/>Ans : B<br\/>Explanation: According to the formula,<br\/>Speed of the stream = (1\/2)(Downstream Speed \u2013 Upstream Speed)<br\/>Speed of the stream = (1\/2)(26-16) = (1\/2) \u00d7 10 = 5 km\/hr<\/p> <\/div> <\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-faqs\">FAQs<\/h2>\n\n\n\n<div class=\"schema-faq wp-block-yoast-faq-block\"><div class=\"schema-faq-section\" id=\"faq-question-1703161958994\"><strong class=\"schema-faq-question\">How do you solve Boats and Streams problems in aptitude?<\/strong> <p class=\"schema-faq-answer\">Firstly read and analyse the questions two-three times before attempting to solve them on your examination asnwer sheet.<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161976604\"><strong class=\"schema-faq-question\">In which exam does Boats and Streams Questions come?<\/strong> <p class=\"schema-faq-answer\">There are various exams like quantitative aptitude section of major government exams such as IBPS PO, IBPS Clerk, SBI PO, SBI Junior Associate, RRB Clerk, RRB Scale 1 Officer, SSC CGL, SSC CHSL, LIC Assistant, etc in which these types of questions actually comes in.<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1703161977677\"><strong class=\"schema-faq-question\">Is this tuff to solve these types of problems?<\/strong> <p class=\"schema-faq-answer\">No by using common sense and correct formulas you can easily solve these types of questions.<\/p> <\/div> <\/div>\n\n\n\n<p>This was all about the \u201c20 + Boats and Streams Questions and Answers | Quantitative Aptitude\u201d.&nbsp; For more such informative blogs, check out our <a href=\"https:\/\/leverageedu.com\/discover\/category\/indian-exams\/study-material\/\"><strong>Study Material Section<\/strong><\/a>, or you can learn more about us by visiting our <a href=\"https:\/\/leverageedu.com\/discover\/category\/indian-exams\/\">&nbsp;<strong>Indian exams<\/strong><\/a> page.<\/p>\n","protected":false},"excerpt":{"rendered":"Boats and streams questions are the mathematical questions that come into various competitive exams like quantitative aptitude section&hellip;\n","protected":false},"author":102,"featured_media":802070,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"editor_notices":[],"footnotes":""},"categories":[369,484,396],"tags":[],"class_list":{"0":"post-801954","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-indian-exams","8":"category-quantitative-aptitude","9":"category-study-material"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.3 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>20 + Boats and Streams Questions and 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1. A person can swim in water with a speed of 13 km\/hr in still water. If the speed of the stream is 4 km\/hr, what will be the time taken by the person to go 68 km downstream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"2.5 hours   <br\/>3 hours   <br\/>4 hours   <br\/>3.5 hours   <br\/>4.5 hours<br\/><br\/>Answer: (3) 4 hours<br\/>Solution:<br\/>Downstream Speed = (13+4) km\/hr = 17 km\/hr<br\/>To travel 68 km downstream.<br\/>Time taken = 68\/17 = 4 hours","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146357529","position":2,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146357529","name":"Q 2. In one hour, a boat goes 13 km\/hr in the direction of the stream and 7 km\/hr against the direction of the stream. What will be the speed of the boat in still water?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":" 8 km\/hr   <br\/>10 km\/hr   <br\/>14 km\/hr   <br\/>6 km\/hr   <br\/>Cannot Be Determined  <br\/><br\/>Answer: (2) 10 km\/hr<br\/>Solution:<br\/>According to the formula,<br\/>Speed of a boat in still water = \u00bd (DownstreamSpeed + UpstreamSpeed)<br\/>Speed of boat in still water = \u00bd (13+7) = \u00bd \u00d7 20 = 10 km\/hr<br\/>","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146358577","position":3,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146358577","name":"Q 3. A woman can row upstream at 16 km\/hr and downstream at 26 km\/hr. What is the speed of the stream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"5 km\/hr<br\/>2 km\/hr<br\/>4.5 km\/hr<br\/>21 km\/hr<br\/><br\/>Answer: (1) 5km\/hr<br\/>Solution:<br\/>According to the formula,<br\/>Speed of the stream = \u00bd (Downstream Speed \u2013 Upstream Speed)<br\/>Speed of the stream = \u00bd (26-16) = \u00bd \u00d7 10 = 5 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146360843","position":4,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146360843","name":"Q 4. A speedboat, whose speed in 15 km\/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. What is the speed of the stream in km\/hr?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"2.5 km\/hr   <br\/>3.5 km\/hr   <br\/>4 km\/hr   <br\/>5 km\/hr   <br\/>3.25 km\/hr  <br\/><br\/>Answer: (4) 5 km\/hr<br\/>Solution:<br\/>Let the speed of the stream be x km\/hr<br\/>Upstream Speed = 15 + x<br\/>Downstream Speed = 15 \u2013 x<br\/>So, {30 \/ (15+x)} + {30 \/ (15-x)} = 4 \u00bd (4 hours 30 minutes)<br\/>\u21d2 {900 \/ (225-x2)} = 9\/2<br\/>\u21d2 9x2 = 225<br\/>\u21d2x2 = 25<br\/>\u21d2x = 5","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146363047","position":5,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146363047","name":"Q 5. A boat is moving 2 km against the current of the stream in 1 hour and moves 1 km in the direction of the current in 10 minutes. How long will it take the boat to go 5 km in stationary water?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1 hr 20 minutes   <br\/>1 hr 30 minutes   <br\/>1 hr 15 minutes   <br\/>30 minutes   <br\/>45 minutes  <br\/><br\/>Answer: (3) 1 hr 15 minutes<br\/>Solution:\u00a0<br\/>Downstream = (1\/10 \u00d7 60) = 6 km\/hr<br\/>Upstream = 2 km\/hr<br\/>Speed in still water = \u00bd (6+2) = 4 km\/hr<br\/>So, the time is taken by the boat to go 5km in stationary water = 5\/4 hrs = 1 \u00bc hrs = 1 hr 15 minutes","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146811784","position":6,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146811784","name":"Q 6. A boat takes 27 hrs to travel a distance upstream and takes 9hrs to travel the same distance downstream. If the speed of the boat in still water is 12km\/hr, then what is the velocity of the stream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"4km\/hr<br\/>6km\/hr<br\/>8km\/hr<br\/>10km\/hr<br\/><br\/>Ans : B<br\/>Explanation: Let the velocity of the stream be y km\/hr<br\/>Then the speed of the downstream = (12 + y)km\/hr<br\/>The speed of the upstream = (12 \u2013 y)km\/hr<br\/>9 (12 + y) = 27 (12 \u2013 y)<br\/>108 + 9y = 324 \u2013 27y<br\/>27y + 9y = 324 - 108<br\/>36y = 216<br\/>y = 6 km\/hr\u00a0","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146812712","position":7,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146812712","name":"Q 7. A boat covers 12 km upstream and 18km downstream in 3hrs while it covers 18 km upstream and 12km downstream in 3(1\/4) hrs the velocity of the the boat upstream and downstream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"12km\/hr<br\/>14km\/hr<br\/>16km\/hr<br\/>18km\/hr<br\/><br\/>Ans : A<br\/>Explanation: Let rate of upstream be 'x'km\/hr and downstream be 'y' km\/hr<br\/>Then, 12\/x + 18\/y = 3 -->1<br\/>18\/x + 12\/y =13\/4 -->2<br\/>Adding 1 and 2 we get,<br\/>30\/x + 30\/y = 25\/4<br\/>1\/x + 1\/y +=5\/24 -->3<br\/>Subtracting 1 and 2 we get<br\/>1\/x \u2013 1\/y = 1\/24 -->4<br\/>Adding 3 and 4 we get,<br\/>2\/x = 6\/24 ; x= 8 ->5<br\/>Substitute 5 in 3 we get, y=12<br\/>Speed of upstream = 8 km\/hr and downstream = 12 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146813625","position":8,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146813625","name":"Q 8. If a boy rows 8 km downstream in 6 hours and 4 km upstream in 4 hours then how long will he take to cover 16 km in stationary (still) water?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"8<br\/>14<br\/>22<br\/>16<br\/><br\/>Ans : B<br\/>Explanation: Distance covered in downstream = 8 km<br\/>Time taken in downstream = 6 hours.<br\/>Rate of downstream = 8\/6=4\/3 km\/hr<br\/>Distance covered in upstream = 4 km<br\/>Time taken in upstream = 4hours.<br\/>Rate of upstream = 4\/4 = 1 km\/hr<br\/>Speed in still water = (1\/2)(4\/3+1) = 7\/6km\/hr<br\/>Time Taken to cover 16 km in still water = 16*6\/7=14hrs (approximately)<br\/>","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146814572","position":9,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146814572","name":"Q 9. A boat takes 24 hours to cover 128 km downstream and 16 hours to cover 64 km upstream. Then the speed of the boat in still water is:","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"14\/3<br\/>8\/7<br\/>3\/2<br\/>9\/5<br\/><br\/>Explanation: Distance covered in downstream = 128km<br\/>Time taken in downstream = 24 hours.<br\/>Rate of downstream = distance \/ time = a = 128 km \/24 hours = 16\/3km\/hr<br\/>Distance covered in upstream = 64km<br\/>Time taken in upstream = 16 hours.<br\/>Rate of upstream = distance \/ time = b = 64km \/16hours = 4 km\/hr.<br\/>Speed in still water = (a + b) \/ 2 = (1\/2)(16\/3+4) km\/hr = (1\/2)(28\/3)km\/hr<br\/>= 14\/3km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146815607","position":10,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703146815607","name":"Q 10. A pedal boat goes 12km upstream and 14km downstream in 3hrs. It goes 15km upstream and 10.5km downstream in 3 hrs 15mints. The speed of the boat in still water is:","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"10<br\/>15<br\/>20<br\/>25<br\/><br\/>Ans : A<br\/>Explanation: Let 'x' be the speed of the boat in still water<br\/>Let 'y' be the speed of the current.<br\/>Pedal boat will travel downstream at (x + y)km\/hr and upstream (x \u2013 y)km\/hr<br\/>Therefore 14\/x +y + 12\/ x \u2013y = 3<br\/>10.5\/(x+y) + 15\/(x-y) = 13\/4<br\/>70\/(x+y) +60 \/(x-y) =15 -->1<br\/>42 \/(x+y) + 60\/(x-y) = 13 -->2<br\/>From 1 and we get,<br\/>x+y = 14 ; x-y = 6<br\/>Therefore x= 10 ; y = 4<br\/>The speed of the pedalboat is 10 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147109660","position":11,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147109660","name":"Q 11. A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mints to cover a distance of 10km upstream. Find the speed of the river current in km\/hr.","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1kmph<br\/>1.5kmph<br\/>2.0kmph<br\/>2.5kmph<br\/><br\/>Ans : B<br\/>Explanation: Rate downstream = 30 \/ (11\/2) km\/hr<br\/>= 30 * 2 \/ 11 km\/hr<br\/>= 60\/11 km\/hr<br\/>Rate upstream = 10 \/ (17\/4)km\/hr<br\/>= 10 * 4 \/ 17 km\/hr<br\/>= 40 \/ 17 km\/hr<br\/>Speed of current = 1 \/ 2 (a \u2013 b) km\/hr<br\/>=1 \/ 2 (60 \/ 11 \u2013 40 \/ 17)<br\/>= 1.5 km\/hr (approx.)","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147110752","position":12,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147110752","name":"Q 12. A man can row 4 km against the stream in 40mins and return in 36mins. Find the rate of current.","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1\/3kmph<br\/>2\/3kmph<br\/>4\/3kmph<br\/>5\/3kmph<br\/><br\/>Ans : A<br\/>Explanation: Speed of the man (upstream) = (4 \/ 40 * 60) km\/hr<br\/>= 6 km\/hr<br\/>Speed of the man (downstream) = ( 4 \/ 36 * 60) km\/hr<br\/>= (60 \/ 9)km\/hr<br\/>= 20\/3 km\/h<br\/>Rate of the current = \u00bd[downstream speed \u2013 upstream speed]<br\/>= (1\/2) [ 20 \/ 3 \u2013 6] km\/hr<br\/>Rate of the current = 1\/3 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147111638","position":13,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147111638","name":"Q 13. Sakthi rows a boat at 4 km upstream in 1hour and 1 km downstream in 20 minutes. How long will he take to reach 3.5km in still water?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1<br\/>2<br\/>3<br\/>4<br\/><br\/>Ans : A<br\/>Explanation: Upstream Speed = 4\/1 = 4km\/hr<br\/>Downstream Speed = 1\/20 = 0.05 km\/min<br\/>= 0.05*60 = 3 km\/hr<br\/>Hence, speed of boat = 1\/2( Upstream Speed + Downstream Speed)<br\/>= 1\/2 (4+3)km\/hr =3.5 km\/hr<br\/>Thus, the time required to reach the distance of 3.5 km=DistanceCovered\/Speed of boat<br\/>= 3.5\/3.5km\/hr =1 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147112748","position":14,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147112748","name":"Q 14. A motor boat sails 30 km of a river towards upstream in 10hrs. How long will it take to cover the same distance downstream, if the speed of the current is \u00bd of the speed of the boat in still water.","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"8hr<br\/>3.33hr<br\/>5hr<br\/>4.33hr<br\/><br\/>Ans : B<br\/>Explanation: Upstream speed = x \u2013y<br\/>Downstream speed = x + y<br\/>x\u2013 y = 30\/10 = 3km\/hr<br\/>Again x = 2y<br\/>Therefore x \u2013 y = 3<br\/>y= 3km\/hr ; x = 6km\/hr<br\/>Therefore x + y = 9 km\/hr<br\/>Time during downstream = 30\/9 = 3.33hrs","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147113757","position":15,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703147113757","name":"Q 15. Vinny can row 15km\/h in still water and it takes twice as long to row up the stream than to row down. Find the rate of the stream.","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1.8 km\/hr<br\/>3.33 km\/hr<br\/>5 km\/hr<br\/>33 km\/hr<br\/>Solution- 5km\/h<br\/>The ratio between downstream and upstream speed = 2:1<br\/>Let the upstream speed be 2x, then the speed downstream will be x<br\/>Speed is still water = (v+u) \/ 2 = (2x + x) \/ 2 = 3x\/2 = 15 (given)<br\/>Hence, x = 10 km\/h<br\/>Speed of stream = (v-u)\/2 = (20-10)\/2 = 5 km\/h<br\/>","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161655933","position":16,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161655933","name":"16. Mohana can row 80km upstream and 110km downstream in 26 hrs. Also she can 60km upstream and 88km downstream in 20 hrs. Find the speed of the girl in still water and the speed of the current in ratio:","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"5:6<br\/>3:7<br\/>7:9<br\/>8:3<br\/><br\/>Ans : D<br\/>Explanation: Let rate upstream = 'x' km\/hr and<br\/>Rate downstream = 'y' km\/hr<br\/>Then 80\/x + 110\/y = 26 --->1<br\/>60\/x + 88\/y = 20-->2<br\/>By solving 1 and 2<br\/>y= 11 ; x = 5<br\/>Rain in still water = (1\/2) (11 + 5) km\/hr = 8 km\/hr<br\/>Rain of current = (1\/2) (11 \u2013 50) km\/hr = 3 km\/hr<br\/>The required answer is 8:3","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161657253","position":17,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161657253","name":"17. A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"8:3<br\/>5:2<br\/>3:7<br\/>2:4<br\/><br\/>Ans : A<br\/>Explanation: Let the man's rate upstream be 'x' km\/hr and downstream be 'y' km\/hr<br\/>Then distance covered upstream by 4hrs 24mints = distance covered by downstream in 2hrs<br\/>(x * 4 2\/5) = y *2<br\/>22x\/5 = 2y<br\/>Y = 11x\/5<br\/>Required ratio = (y+x\/2) : (y \u2013x\/2)<br\/>= 16x\/10 : 6x\/10<br\/>= 16x : 6x<br\/>= 8:3","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161660685","position":18,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161660685","name":"18. A person can swim in water with a speed of 13 km\/hr in still water. If the speed of the stream is 4 km\/hr, what will be the time taken by the person to go 68 km downstream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1hr<br\/>2hr<br\/>3hr<br\/>4hr<br\/><br\/>Ans : D<br\/>Explanation: Downstream Speed = (13+4) km\/hr = 17 km\/hr<br\/>To travel 68 km downstream.<br\/>Time taken = 68\/17 = 4 hours","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161663243","position":19,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161663243","name":"19. In one hour, a boat goes 13 km\/hr in the direction of the stream and 7 km\/hr against the direction of the stream. What will be the speed of the boat in still water?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"10km\/hr<br\/>20km\/hr<br\/>30km\/hr<br\/>40km\/hr<br\/>Ans : A<br\/>Explanation: According to the formula,<br\/>Speed of a boat in still water = (1\/2) (DownstreamSpeed + UpstreamSpeed)<br\/>Speed of boat in still water = (1\/2) (13+7) = (1\/2) \u00d7 20 = 10 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161664403","position":20,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161664403","name":"20. A woman can row upstream at 16 km\/hr and downstream at 26 km\/hr. What is the speed of the stream?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"1km\/hr<br\/>5km\/hr<br\/>3km\/hr<br\/>9km\/hr<br\/><br\/>Ans : B<br\/>Explanation: According to the formula,<br\/>Speed of the stream = (1\/2)(Downstream Speed \u2013 Upstream Speed)<br\/>Speed of the stream = (1\/2)(26-16) = (1\/2) \u00d7 10 = 5 km\/hr","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161958994","position":21,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161958994","name":"How do you solve Boats and Streams problems in aptitude?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"Firstly read and analyse the questions two-three times before attempting to solve them on your examination asnwer sheet.","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161976604","position":22,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161976604","name":"In which exam does Boats and Streams Questions come?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"There are various exams like quantitative aptitude section of major government exams such as IBPS PO, IBPS Clerk, SBI PO, SBI Junior Associate, RRB Clerk, RRB Scale 1 Officer, SSC CGL, SSC CHSL, LIC Assistant, etc in which these types of questions actually comes in.","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161977677","position":23,"url":"https:\/\/leverageedu.com\/discover\/indian-exams\/exam-prep-boats-and-streams\/#faq-question-1703161977677","name":"Is this tuff to solve these types of problems?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"No by using common sense and correct formulas you can easily solve these types of questions.","inLanguage":"en-US"},"inLanguage":"en-US"}]}},"acf":[],"_links":{"self":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts\/801954","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/users\/102"}],"replies":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/comments?post=801954"}],"version-history":[{"count":0,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts\/801954\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/media\/802070"}],"wp:attachment":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/media?parent=801954"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/categories?post=801954"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/tags?post=801954"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}