{"id":792645,"date":"2023-10-18T10:52:14","date_gmt":"2023-10-18T05:22:14","guid":{"rendered":"https:\/\/leverageedu.com\/discover\/?p=792645"},"modified":"2023-10-18T10:52:14","modified_gmt":"2023-10-18T05:22:14","slug":"ncert-maths-algebra-class-6-chapter-11","status":"publish","type":"post","link":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/","title":{"rendered":"NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF"},"content":{"rendered":"\n<p>In Chapter 11, Algebra &#8211; Class 6, students will be introduced to the concepts of algebra. Students will learn the use of letters to write rules and formulas to talk about any number. Algebra, Class 6 will teach students to determine the value of the unknowns which are commonly represented as letters. The chapter Algebra of Class 6 teaches students about algebraic expressions and their properties. Read through for NCERT Maths Algebra Class 6 (Chapter 11) Notes and Exercise Solutions.<\/p>\n\n\n\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/multiplication-and-division-word-problems\/\"><strong>Multiplication and Division Word Problems<\/strong><\/a><\/p>\n\n\n\n<p class=\"has-text-align-center has-background has-medium-font-size\" style=\"background:linear-gradient(135deg,rgb(255,245,203) 0%,rgb(182,227,212) 100%,rgb(51,167,181) 100%)\"><a href=\"https:\/\/drive.google.com\/file\/d\/1bHbXXuacIXuHcNrbXWtjzn531KNVbm62\/view?usp=sharing\"><strong>Click here to download NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF<\/strong><\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ncert-maths-algebra-class-6-notes-pdf-available\">NCERT Maths Algebra Class 6 Notes &#8211; PDF Available<\/h2>\n\n\n\n<p>Check the topic-wise notes for NCERT Maths Algebra Class 6, Chapter 11 below. We have also provided a downloadable free PDF at the end of these notes so you can download and take a printout to study later when you need quick revision before going to the exam hall.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-topic-1-variables\">Topic 1: Variables<\/h3>\n\n\n\n<p>The word \u2018variable\u2019 means something that can vary, i.e. change. The value of a variable is not fixed. It can take different values.&nbsp;<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>Top 10 Short Maths Tricks for Complex Problems<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-topic-2-rules-from-geometry-using-variables\">Topic 2: Rules from Geometry Using Variables<\/h3>\n\n\n\n<p>We have learned the perimeter and area formulas of the square, rectangle and triangle in the previous chapter. Now, let us learn these formulas in the form of rules using variables. This helps us to write the formulas in a more general and concise way.\u00a0<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Perimeter of Rectangle Formula: <\/strong>The rectangle has 4 sides, having opposite sides of equal lengths.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>Perimeter of Rectangle = 2 \u00d7 (length(l) + breadth(b)) = 2l \u00d7 2b<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\">\n<li><strong>Perimeter of Square Formula: <\/strong>A square has sides of equal lengths.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>Perimeter of Square = 4 \u00d7 Length of a Side (l) = 4l<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p><a href=\"https:\/\/leverageedu.com\/blog\/maths-for-competitive-exams\/\"><strong>Maths for Competitive Exams<\/strong><\/a><\/p>\n\n\n\n<p><strong>Maths Formulas for Class 10<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\" start=\"3\">\n<li><strong>Perimeter of Triangle Formula: <\/strong>Here, we will determine the perimeter of an equilateral triangle. An equilateral triangle has all sides of equal lengths.<\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>Perimeter of an Equilateral Triangle = 3 \u00d7 Length of a Side (l) = 3l<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>We can determine the length of any regular figure in a similar way if we know its number of sides. Therefore, we can determine the perimeter of a regular pentagon in a similar way.<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>Perimeter of a Regular Pentagon = 5 \u00d7 Length of a Side (l) = 5l<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"has-text-align-center has-pale-ocean-gradient-background has-background\"><a href=\"https:\/\/leverageedu.com\/blog\/maths-books-for-competitive-exams\/\"><strong>Maths Books for Competitive Exams<\/strong><\/a><\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-ocean-gradient-background has-background\"><strong>BSc Mathematics: Course, Universities and Scope<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-topic-3-rules-from-arithematic\">Topic 3: Rules from Arithematic<\/h3>\n\n\n\n<p>Here are some simple properties of addition, subtraction, and multiplication that we have studied on whole numbers. Let\u2019s learn the rules of each of these properties using the variables here.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Commutativity of Addition of Two Numbers:<\/strong><\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>a + b = b + a&nbsp;<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\">\n<li><strong>Commutativity of Multiplication of Two Numbers:<\/strong><\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>a \u00d7 b = b \u00d7 a&nbsp;<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<ol class=\"wp-block-list\" start=\"3\">\n<li><strong>Distributivity of numbers:<\/strong><\/li>\n<\/ol>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-pale-cyan-blue-background-color has-background\"><tbody><tr><td>a \u00d7 (b + c) = a \u00d7 b + a \u00d7 c&nbsp;<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background\"><strong>SAT Maths Subject Test<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-topic-4-equation\">Topic 4: Equation<\/h3>\n\n\n\n<p>Any equation is a condition on variables that is satisfied only for a definite value of the variable.\u00a0<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Solution to the Equation: <\/strong>The value of the variable in an equation that satisfies the equation is called a solution to the equation.<\/li>\n<\/ol>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background\">Also Read: <a href=\"https:\/\/leverageedu.com\/blog\/bodmas-questions\/\"><strong>BODMAS Questions<\/strong><\/a><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-ncert-maths-algebra-class-6-chapter-11-exercise-solutions\">NCERT Maths Algebra Class 6 Chapter 11 Exercise Solutions<\/h2>\n\n\n\n<p>Below we have provided solutions for NCERT Maths Algebra Class 6, chapter 11. Go through for answers to some important questions.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-exercise-11-1-solutions\">Exercise 11.1 Solutions<\/h3>\n\n\n\n<p><strong>Q 1.&nbsp; Cadets are marching in a parade. There are 5 cadets in a row. What is the rule which gives the number of cadets, given the number of rows? (Use n for the number of rows.)<\/strong><\/p>\n\n\n\n<p><strong>Ans.<\/strong> Let us assume the number of rows in the parade to be \u201cn\u201d.<\/p>\n\n\n\n<p>The number of cadets in a row = 5<\/p>\n\n\n\n<p>\u2234 Rule for the number of cadets in a row = 5 \u00d7 n = 5n<\/p>\n\n\n\n<p><strong>Q 2. &nbsp; If there are 50 mangoes in a box, how will you write the total number of mangoes in terms of the number of boxes? (Use b for the number of boxes.)<\/strong><\/p>\n\n\n\n<p><strong>Ans.<\/strong> Let us assume the number of boxes to be \u201cb\u201d.<\/p>\n\n\n\n<p>The number of mangoes in each box = 50<\/p>\n\n\n\n<p>\u2234 Rule for the total number of mangoes in terms of the number of boxes = 50 \u00d7 b = 50b<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/commerce-with-maths\/\"><strong>Top 20 Career Options in Commerce with Maths Stream<\/strong><\/a><\/p>\n\n\n\n<p><strong>Q 3. The teacher distributes 5 pencils per student. Can you tell how many pencils are needed, given the number of students? (Use s for the number of students.)<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Let us assume the number of students to be \u201cs\u201d.<\/p>\n\n\n\n<p>The number of pencils distributed per student = 5<\/p>\n\n\n\n<p>\u2234 Rule for the total number of pencils needed = 5 \u00d7 s = 5s<\/p>\n\n\n\n<p><strong>Q 4. A bird flies 1 kilometer in one minute. Can you express the distance covered by the bird in terms of its flying time in minutes? (Use t for flying time in minutes.)<\/strong><\/p>\n\n\n\n<p><strong>Ans.<\/strong> Let us assume the flying time of the bird in minutes to be \u201ct\u201d.<\/p>\n\n\n\n<p>The number of kilometers covered by the bird in a minute = 1<\/p>\n\n\n\n<p>\u2234 Rule for the total distance covered by the bird = 1 \u00d7 t = 1t km = t km<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>NCERT Class 8 Maths Syllabus<\/strong><\/p>\n\n\n\n<p><strong>Q 5. Radha is drawing a dot Rangoli (a beautiful pattern of lines joining dots) with chalk powder. She has 9 dots in a row. How many dots will her Rangoli have for r rows? How many dots are there if there are 8 rows? If there are 10 rows?<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Let us assume the number of rows in Radha\u2019s rangoli to be \u201cr\u201d.<\/p>\n\n\n\n<p>The number of dots in a row = 9<\/p>\n\n\n\n<p>\u2234 The total number of dots in r number of rows = 9 \u00d7 r = 9r<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Now, given: r = 8<\/li>\n<\/ol>\n\n\n\n<p>The total number of dots in 8 rows = 9 \u00d7 8 = 72 dots<\/p>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\">\n<li>Given, r = 10 rows<\/li>\n<\/ol>\n\n\n\n<p>The total number of dots in 10 rows = 9 \u00d7 10 = 90 dots<\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/ba-mathematics-syllabus\/\"><strong>BA Mathematics Syllabus<\/strong><\/a><\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/arts-with-maths\/\"><strong>Pathways for Arts with Maths Students<\/strong><\/a><\/p>\n\n\n\n<p><strong>Q 6. Leela is Radha&#8217;s younger sister. Leela is 4 years younger than Radha. Can you write Leela&#8217;s age in terms of Radha&#8217;s age? Take Radha&#8217;s age to be x years.<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Let us assume Radha\u2019s age to be \u201cx\u201d years.<\/p>\n\n\n\n<p>Given: Leela is 4 years younger than Radha.<\/p>\n\n\n\n<p>\u2234 Leela\u2019s age = (x &#8211; 4) years<\/p>\n\n\n\n<p><strong>Q 7. Mother has made laddus. She gives some laddoos to guests and family members; still, 5 laddus remain. If the number of laddoos mother gave away is l, how many laddoos did she make?<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Let us assume the number of laddoos given away by mother to be \u201cl\u201d.<\/p>\n\n\n\n<p>Given: Number of remaining laddoos = 5&nbsp;<\/p>\n\n\n\n<p>\u2234 Total number of laddoos made by mother = l + 5 laddoos<\/p>\n\n\n\n<p><strong>Q 8.&nbsp; Oranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes and still 10 oranges remain outside. If the number of oranges in a small box is taken to be x, what is the number of oranges in the larger box?<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Let us assume the number of oranges in the small box to be \u201cx\u201d.<\/p>\n\n\n\n<p>Oranges from the larger box fill up 2 small boxes. So, the total number of oranges in smaller boxes is 2x and still 10 oranges remain out of the box.<\/p>\n\n\n\n<p>\u2234 Total number of oranges in the larger box = 2x + 10 oranges&nbsp;<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/career-after-bsc-maths\/\"><strong>Career after BSc Maths<\/strong><\/a><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-exercise-11-2-solutions\">Exercise 11.2 Solutions<\/h3>\n\n\n\n<p><strong>Q 1. The side of a regular hexagon is denoted by l. Express the perimeter of the hexagon using l.<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>A regular hexagon has all sides of equal length. Hence, the perimeter of a regular hexagon can be determined by adding all its sides.&nbsp;<\/p>\n\n\n\n<p>\u2234 The perimeter of the given regular hexagon = 6l<\/p>\n\n\n\n<p><strong>Q 2. A cube is a three-dimensional figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.&nbsp;<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img  decoding=\"async\"  src=\"data:image\/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABAQMAAAAl21bKAAAAA1BMVEUAAP+KeNJXAAAAAXRSTlMAQObYZgAAAAlwSFlzAAAOxAAADsQBlSsOGwAAAApJREFUCNdjYAAAAAIAAeIhvDMAAAAASUVORK5CYII=\"  alt=\"\"  class=\" pk-lazyload\"  data-pk-sizes=\"auto\"  data-pk-src=\"https:\/\/lh7-us.googleusercontent.com\/WWWn-O7QWm9N-gekD7UPVZybISpZbAiPQq0NxjAdSPuQ2M8B7xStB-2okDhxlNXrm9nulI-I6pBdvoo7FRj0IZ5QE1GTUZ-0XDSkN1BL5lTHoTq3EOgrW-__Afp9CIt-V5ZYw0Z5Fnc-dHJwZjxDaAE\" ><\/figure>\n\n\n\n<p><strong>Ans. <\/strong>Given, a three-dimensional cube having 6 identical square faces. Each square face has 4 edges.&nbsp;&nbsp;<\/p>\n\n\n\n<p>The total number of uncommon edges = 12&nbsp;<\/p>\n\n\n\n<p>Length of each edge = l<\/p>\n\n\n\n<p>\u2234 The formula for the total length of the edges of a cube = 12l<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>Career in Mathematics and Computing<\/strong><\/p>\n\n\n\n<p><strong>Q 3. The diameter of a circle is a line that joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure, AB is the diameter of the circle; C is its centre.) Express the diameter of the circle (d) in terms of its radius (r).<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img  decoding=\"async\"  src=\"data:image\/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAEAAAABAQMAAAAl21bKAAAAA1BMVEUAAP+KeNJXAAAAAXRSTlMAQObYZgAAAAlwSFlzAAAOxAAADsQBlSsOGwAAAApJREFUCNdjYAAAAAIAAeIhvDMAAAAASUVORK5CYII=\"  alt=\"\"  class=\" pk-lazyload\"  data-pk-sizes=\"auto\"  data-pk-src=\"https:\/\/lh7-us.googleusercontent.com\/4ZZnyUziBC9LPiW8tfdD-qn7xAgrOTDgFwpeQFEZ7CvXyGV1QzuVxe2YG0nt6vdk3LKSXVBRUMNoD7WWoeGBogGbfHwSwBH8J4Ok6Gyq5zGA4zQiEMbfMwXZ57IFdOsMUx3rrFoR1qlVz7uM5VxzujY\" ><\/figure>\n\n\n\n<p><strong>Ans.<\/strong> A radius passes through the center of the circle and touches a point on the circle. Now, as given &#8211; the diameter of a circle is a line that joins two points on the circle and also passes through the center of the circle.<\/p>\n\n\n\n<p>Let us assume the length of the radius of the given circle to be \u201cr\u201d.<\/p>\n\n\n\n<p>\u2234 The length of the diameter AB = 2 \u00d7 r = 2r<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/courses-after-12th-commerce-without-maths\/\"><strong>Courses after 12th Commerce without Maths<\/strong><\/a><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-exercise-11-3-solutions\">Exercise 11.3 Solutions<\/h3>\n\n\n\n<p><strong>Q 1.&nbsp; Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed.<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>z +1, z \u2013 1, y + 17, y \u2013 17&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>17y, y\/17, 5z<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Ans. <\/strong>The answers to each of the given parts are given below.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>In (z + 1), 1 is added to z, so it is the function of addition.<\/li>\n<\/ol>\n\n\n\n<p>In (z &#8211; 1), 1 is subtracted from z, so it is the function of subtraction.<\/p>\n\n\n\n<p>In (y + 17), 17 is added to y, so it is the function of addition.<\/p>\n\n\n\n<p>In (y &#8211; 17), 17 is subtracted from y, so it is the function of subtraction.<\/p>\n\n\n\n<ol class=\"wp-block-list\" start=\"2\">\n<li>In 17y, 17 is multiplied by y, so it is the function of multiplication.<\/li>\n<\/ol>\n\n\n\n<p>In y\/17, y is divided by 17, so it is an operation of division.&nbsp;<\/p>\n\n\n\n<p>In 5z, 5 is multiplied by y, so it is the function of multiplication.<\/p>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><strong>NCERT Class 11 Maths Solutions &amp; Study Notes<\/strong><\/p>\n\n\n\n<p><strong>Q 2. Give expressions for the following cases.<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>7 added to p&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>7 subtracted from p<\/strong><\/li>\n\n\n\n<li><strong>p multiplied by 7&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>p divided by 7<\/strong><\/li>\n\n\n\n<li><strong>7 subtracted from \u2013 m&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>\u2013 p multiplied by 5<\/strong><\/li>\n\n\n\n<li><strong>\u2013 p divided by 5&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>p multiplied by \u2013 5<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Ans. <\/strong>The expressions of each of the given cases are given below.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>7 + p<\/li>\n\n\n\n<li>p &#8211; 7<\/li>\n\n\n\n<li>7p<\/li>\n\n\n\n<li>p\/7<\/li>\n\n\n\n<li>-m &#8211; 7<\/li>\n\n\n\n<li>-5p<\/li>\n\n\n\n<li>-p\/5<\/li>\n\n\n\n<li>-5p<\/li>\n<\/ol>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/explore\/career-counselling\/maths-teacher-interview-questions\/\"><strong>Maths Teacher Interview Questions with Sample Answers<\/strong><\/a><\/p>\n\n\n\n<p><strong>Q 3.&nbsp; Give expressions in the following cases.<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>11 added to 2m&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>11 subtracted from 2m<\/strong><\/li>\n\n\n\n<li><strong>5 times y to which 3 is added&nbsp;<\/strong><\/li>\n\n\n\n<li><strong>5 times y from which 3 is subtracted<\/strong><\/li>\n\n\n\n<li><strong>y is multiplied by \u2013 8<\/strong><\/li>\n\n\n\n<li><strong>y is multiplied by \u2013 8 and then 5 is added to the result<\/strong><\/li>\n\n\n\n<li><strong>y is multiplied by 5 and the result is subtracted from 16<\/strong><\/li>\n\n\n\n<li><strong>y is multiplied by \u2013 5 and the result is added to 16.<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Ans. <\/strong>The expressions of each of the given cases are given below.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>2m + 11<\/li>\n\n\n\n<li>2m &#8211; 11<\/li>\n\n\n\n<li>5y + 3<\/li>\n\n\n\n<li>5y &#8211; 3<\/li>\n\n\n\n<li>-8y<\/li>\n\n\n\n<li>-8y + 5<\/li>\n\n\n\n<li>16 &#8211; 5y<\/li>\n\n\n\n<li>&nbsp;-5y + 16<\/li>\n<\/ol>\n\n\n\n<p class=\"has-text-align-center has-pale-cyan-blue-background-color has-background has-medium-font-size\"><a href=\"https:\/\/leverageedu.com\/blog\/career-options-in-commerce-without-maths\/\"><strong>Courses and Career Options in Commerce Without Maths in 2023<\/strong><\/a><\/p>\n\n\n\n<h3 class=\"wp-block-heading\" id=\"h-exercise-11-4-solutions\">Exercise 11.4 Solutions<\/h3>\n\n\n\n<p><strong>Q 1. Take Sarita\u2019s present age to be y years<\/strong><\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>What will be her age 5 years from now?<\/strong><\/li>\n\n\n\n<li><strong>What was her age 3 years ago?<\/strong><\/li>\n\n\n\n<li><strong>Sarita\u2019s grandfather is 6 times her age. What is the age of her grandfather?<\/strong><\/li>\n\n\n\n<li><strong>Grandmother is 2 years younger than grandfather. What is the grandmother&#8217;s age?<\/strong><\/li>\n\n\n\n<li><strong>Sarita\u2019s father\u2019s age is 5 years more than 3 times Sarita\u2019s age. What is her father&#8217;s age?<\/strong><\/li>\n<\/ol>\n\n\n\n<p><strong>Ans. <\/strong>Given that Sarita\u2019s present age is \u201cy\u201d years. The answers are given below.&nbsp;<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Sarita\u2019s age 5 years from now will be (5 + y) years.<\/li>\n\n\n\n<li>Sarita\u2019s age 3 years ago was (y &#8211; 3).<\/li>\n\n\n\n<li>Sarita\u2019s grandfather\u2019s age is 6y years.<\/li>\n\n\n\n<li>Grandmother\u2019s age = Grandfather\u2019s age &#8211; 2 years = (6y &#8211; 2) years<\/li>\n\n\n\n<li>Sarita\u2019s father\u2019s age is (3y + 5) years.&nbsp;<\/li>\n<\/ol>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background\"><strong>CBSE Class 9 Maths Syllabus<\/strong><\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background\"><a href=\"https:\/\/leverageedu.com\/learn\/business-mathematics\/\"><strong>Business Mathematics<\/strong><\/a><\/p>\n\n\n\n<p class=\"has-pale-cyan-blue-background-color has-background\"><strong>Applied Mathematics and Computation<\/strong><\/p>\n\n\n\n<p><strong>Q 2. The length of a rectangular hall is 4 meters less than 3 times the breadth of the hall. What is the length, if the breadth is b meters?<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Given: the length of the breadth of the rectangular hall to be \u201cb\u201d metres.&nbsp;<\/p>\n\n\n\n<p>\u2234 Length of the rectangular hall = (3b &#8211; 4) m<\/p>\n\n\n\n<p><strong>Q 3. A rectangular box has a height of h cm. Its length is 5 times the height and breadth is 10 cm less than the length. Express the length and the breadth of the box in terms of the height.<\/strong><\/p>\n\n\n\n<p><strong>Ans. <\/strong>Given: height = h cm<\/p>\n\n\n\n<p>The length of the box is 5 times the length of height, so, length = 5h cm&nbsp;<\/p>\n\n\n\n<p>The breadth of the box is 10 cm less than the length of the box, so, breadth = (5h &#8211; 10) cm<\/p>\n\n\n\n<figure class=\"wp-block-embed is-type-video is-provider-youtube wp-block-embed-youtube wp-embed-aspect-16-9 wp-has-aspect-ratio\"><div class=\"wp-block-embed__wrapper\">\n<iframe loading=\"lazy\" title=\"Introduction - &quot;Algebra&quot; - Chapter 11 - Class 6th Maths\" width=\"1200\" height=\"675\" src=\"https:\/\/www.youtube.com\/embed\/T8XY_wL9G1o?feature=oembed\" frameborder=\"0\" allow=\"accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share\" allowfullscreen><\/iframe>\n<\/div><figcaption class=\"wp-element-caption\">Source: Mathematics Class VI<\/figcaption><\/figure>\n\n\n\n<p>Check out Maths Class 6 Notes and Exercise Solutions for other chapters below.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-table\" style=\"font-size:18px\"><table class=\"has-background\" style=\"background:linear-gradient(135deg,rgb(255,245,203) 0%,rgb(182,227,212) 100%,rgb(51,167,181) 100%)\"><tbody><tr><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-ncert-maths-chapter-1-knowing-our-numbers\/\"><strong>Maths Class 6 Chapter 1 Notes &amp; Solutions<\/strong><\/a><\/td><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-ncert-maths-chapter-2-whole-numbers\/\"><strong>Maths Class 6 Chapter 2 Notes &amp; Solutions<\/strong><\/a><\/td><\/tr><tr><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-ncert-maths-chapter-3-playing-with-numbers\/\"><strong>Maths Class 6 Chapter 3 Notes &amp; Solutions<\/strong><\/a><\/td><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-ncert-maths-chapter-4-basic-geometrical-ideas\/\"><strong>Maths Class 6 Chapter 4 Notes &amp; Solutions<\/strong><\/a><\/td><\/tr><tr><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-ncert-maths-chapter-5-understanding-elementary-shapes\/\"><strong>Maths Class 6 Chapter 5 Notes &amp; Solutions<\/strong><\/a><\/td><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-ncert-class-6-maths-chapter-6-integers\/\"><strong>Maths Class 6 Chapter 6 Notes &amp; Solutions<\/strong><\/a><\/td><\/tr><tr><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-ncert-class-6-maths-chapter-7-fractions\/\"><strong>Maths Class 6 Chapter 7 Notes &amp; Solutions<\/strong><\/a><\/td><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-ncert-maths-class-6-chapter-8-decimals\/\"><strong>Maths Class 6 Chapter 8 Notes &amp; Solutions<\/strong><\/a><\/td><\/tr><tr><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/ncert-study-material\/cbse-ncert-maths-class-6-chapter-9-notes\/\"><strong>Maths Class 6 Chapter 9 Notes &amp; Solutions<\/strong><\/a><\/td><td><a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-ncert-class-6-maths-chapter-10\/\"><strong>Maths Class 6 Chapter 10 Notes &amp; Solutions<\/strong><\/a><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"h-faqs\">FAQs<\/h2>\n\n\n\n<div class=\"schema-faq wp-block-yoast-faq-block\"><div class=\"schema-faq-section\" id=\"faq-question-1697606195719\"><strong class=\"schema-faq-question\">Q.1. How to score 100 marks in Maths Class 6?<\/strong> <p class=\"schema-faq-answer\">Ans: If you wish to score an absolute 100 marks in your Class 6 Maths exam, then, you must prepare for all the chapters in detail. You need to practice your exercise questions and grasp any exceptional trick to solve a particular question. Try solving your exercises 2-3 times before appearing for your maths exam.<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1697606232733\"><strong class=\"schema-faq-question\">Q.2. What is the rule for finding the perimeter of a rectangle?<\/strong> <p class=\"schema-faq-answer\">Ans: The rule for finding the perimeter of a rectangle is (2l + 2b).<\/p> <\/div> <div class=\"schema-faq-section\" id=\"faq-question-1697606255400\"><strong class=\"schema-faq-question\">Q.3. What is the rule for finding the perimeter of a regular triangle?<\/strong> <p class=\"schema-faq-answer\">Ans: The rule for finding the perimeter of a regular triangle is 3l.<\/p> <\/div> <\/div>\n\n\n\n<p>This was all about NCERT Maths Algebra Class 6, chapter 11 in which we studied the use of variables to make certain rules and that mathematical operations can be operated on variables when we need to determine an unknown value for a given quantity. Download the NCERT Maths Algebra Class 6 Notes and Exercise Solutions to ace your exam preparations. Follow the <a href=\"https:\/\/leverageedu.com\/discover\/school-education\/cbse-class-6-maths-notes\/\"><strong>CBSE Class 6 Maths Notes<\/strong><\/a> for more such chapter notes and important questions and answers for preparation for CBSE Class 6 Maths.&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"In Chapter 11, Algebra &#8211; Class 6, students will be introduced to the concepts of algebra. Students will&hellip;\n","protected":false},"author":70,"featured_media":792659,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"editor_notices":[],"footnotes":""},"categories":[477,389],"tags":[],"class_list":{"0":"post-792645","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ncert-study-material","8":"category-school-education"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v27.3 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF | Leverage Edu Discover<\/title>\n<meta name=\"description\" content=\"NCERT Maths Algebra Class 6 introduces to the concepts of algebra to students. 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Download important questions and answers free PDF.","og_url":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/","og_site_name":"Leverage Edu Discover","article_published_time":"2023-10-18T05:22:14+00:00","og_image":[{"width":1024,"height":640,"url":"https:\/\/blogassets.leverageedu.com\/media\/uploads\/sites\/9\/2023\/10\/13134044\/Class-6-Maths-Chapter-11.png","type":"image\/png"}],"author":"Priya Garg","twitter_card":"summary_large_image","twitter_misc":{"Written by":"Priya Garg","Est. reading time":"14 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#article","isPartOf":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/"},"author":{"name":"Priya Garg","@id":"https:\/\/leverageedu.com\/discover\/#\/schema\/person\/ae2b8edfd808932c900b153720cb6488"},"headline":"NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF","datePublished":"2023-10-18T05:22:14+00:00","mainEntityOfPage":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/"},"wordCount":2287,"commentCount":0,"image":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#primaryimage"},"thumbnailUrl":"https:\/\/blogassets.leverageedu.com\/media\/uploads\/sites\/9\/2023\/10\/13134044\/Class-6-Maths-Chapter-11.png","articleSection":["NCERT Study Material","School Education"],"inLanguage":"en-US","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#respond"]}]},{"@type":["WebPage","FAQPage"],"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/","url":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/","name":"NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF | Leverage Edu Discover","isPartOf":{"@id":"https:\/\/leverageedu.com\/discover\/#website"},"primaryImageOfPage":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#primaryimage"},"image":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#primaryimage"},"thumbnailUrl":"https:\/\/blogassets.leverageedu.com\/media\/uploads\/sites\/9\/2023\/10\/13134044\/Class-6-Maths-Chapter-11.png","datePublished":"2023-10-18T05:22:14+00:00","author":{"@id":"https:\/\/leverageedu.com\/discover\/#\/schema\/person\/ae2b8edfd808932c900b153720cb6488"},"description":"NCERT Maths Algebra Class 6 introduces to the concepts of algebra to students. Download important questions and answers free PDF.","breadcrumb":{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#breadcrumb"},"mainEntity":[{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606195719"},{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606232733"},{"@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606255400"}],"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#primaryimage","url":"https:\/\/blogassets.leverageedu.com\/media\/uploads\/sites\/9\/2023\/10\/13134044\/Class-6-Maths-Chapter-11.png","contentUrl":"https:\/\/blogassets.leverageedu.com\/media\/uploads\/sites\/9\/2023\/10\/13134044\/Class-6-Maths-Chapter-11.png","width":1024,"height":640,"caption":"Class 6 Maths Chapter 11"},{"@type":"BreadcrumbList","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/leverageedu.com\/discover\/"},{"@type":"ListItem","position":2,"name":"NCERT Maths Algebra Class 6 Chapter 11 Notes and Exercise Solutions PDF"}]},{"@type":"WebSite","@id":"https:\/\/leverageedu.com\/discover\/#website","url":"https:\/\/leverageedu.com\/discover\/","name":"Leverage Edu Discover","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/leverageedu.com\/discover\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/leverageedu.com\/discover\/#\/schema\/person\/ae2b8edfd808932c900b153720cb6488","name":"Priya Garg","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/secure.gravatar.com\/avatar\/1e028a2a56bf6f8eebac0d9de0f2ef837449d104d77ff5725894d5deaa8c24f0?s=96&d=mm&r=g","url":"https:\/\/secure.gravatar.com\/avatar\/1e028a2a56bf6f8eebac0d9de0f2ef837449d104d77ff5725894d5deaa8c24f0?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/1e028a2a56bf6f8eebac0d9de0f2ef837449d104d77ff5725894d5deaa8c24f0?s=96&d=mm&r=g","caption":"Priya Garg"},"description":"Hi! I am Priya. I provide all sorts of educational content. Working in the content domain for the past seven years, I give the most precise student-friendly information. Professionally, I am a Chemist. So, ethically I don't let any error pass on to the content. All my content is fact-based and contains detailed knowledge of the subject.","sameAs":["http:\/\/www.linkedin.com\/in\/priya-garg-ba4478134"],"url":"https:\/\/leverageedu.com\/discover\/author\/priya\/"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606195719","position":1,"url":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606195719","name":"Q.1. How to score 100 marks in Maths Class 6?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"Ans: If you wish to score an absolute 100 marks in your Class 6 Maths exam, then, you must prepare for all the chapters in detail. You need to practice your exercise questions and grasp any exceptional trick to solve a particular question. Try solving your exercises 2-3 times before appearing for your maths exam.","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606232733","position":2,"url":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606232733","name":"Q.2. What is the rule for finding the perimeter of a rectangle?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"Ans: The rule for finding the perimeter of a rectangle is (2l + 2b).","inLanguage":"en-US"},"inLanguage":"en-US"},{"@type":"Question","@id":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606255400","position":3,"url":"https:\/\/leverageedu.com\/discover\/school-education\/ncert-maths-algebra-class-6-chapter-11\/#faq-question-1697606255400","name":"Q.3. What is the rule for finding the perimeter of a regular triangle?","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"Ans: The rule for finding the perimeter of a regular triangle is 3l.","inLanguage":"en-US"},"inLanguage":"en-US"}]}},"acf":[],"_links":{"self":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts\/792645","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/users\/70"}],"replies":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/comments?post=792645"}],"version-history":[{"count":0,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/posts\/792645\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/media\/792659"}],"wp:attachment":[{"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/media?parent=792645"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/categories?post=792645"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/leverageedu.com\/discover\/wp-json\/wp\/v2\/tags?post=792645"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}