Download<\/strong><\/a><\/div>\n\n\n\nCBSE Class 6<\/strong> NCERT Maths Chapter 6 Integers Notes and Important Exercise Questions and Answers Free PDF<\/strong><\/a><\/p>\n\n\n\nExplore all the Chapters of Class 6 Mathematics:-<\/strong><\/p>\n\n\n\nChapter 1<\/strong><\/a><\/td>Chapter 2<\/strong><\/a><\/td>Chapter 3<\/strong><\/a><\/td>Chapter 4<\/strong><\/a><\/td><\/tr>Chapter 5<\/strong><\/a><\/td>Chapter 6<\/td> Chapter 7<\/strong><\/a><\/td>Chapter 8<\/strong><\/a><\/td><\/tr>Chapter 9<\/strong><\/a><\/td>Chapter 10<\/strong><\/a><\/td>Chapter 11<\/strong><\/td>Chapter 12<\/strong><\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\nImportant Questions in NCERT Class 6 Maths Chapter 6: Free PDF Download<\/h2>\n\n\n\n Below we have provided some important exercise questions and their solutions from Chapter 6 of Maths for Class 6. <\/p>\n\n\n\n
Exercise 6.1<\/h3>\n\n\n\n Q 1. Write opposites of the following :<\/strong><\/p>\n\n\n\n\nIncrease in weight <\/strong><\/li>\n\n\n\n30 km north <\/strong><\/li>\n\n\n\nLoss of Rs 700 <\/strong><\/li>\n\n\n\n100 m above sea level<\/strong><\/li>\n<\/ol>\n\n\n\nAns.<\/strong> The opposites of each of the given cases are given below.<\/p>\n\n\n\n\nThe opposite of an increase in weight is a decrease in weight.<\/li>\n\n\n\n The opposite of 30 km north is 30 km south.<\/li>\n\n\n\n The opposite of the loss of Rs 700 is the gain of Rs 700. <\/li>\n\n\n\n The opposite of 100 m above sea level is 100 m below the sea level.<\/li>\n<\/ol>\n\n\n\nQ 2. Represent the following numbers as integers with appropriate signs.<\/strong><\/p>\n\n\n\n\nAn aeroplane is flying at a height two thousand metre above the ground.<\/strong><\/li>\n\n\n\nA submarine is moving at a depth, eight hundred metre below the sea level.<\/strong><\/li>\n\n\n\nA deposit of rupees two hundred.<\/strong><\/li>\n\n\n\nWithdrawal of rupees seven hundred.<\/strong><\/li>\n<\/ol>\n\n\n\nAns.<\/strong> Let us write each case in numbers with appropriate signs as:<\/p>\n\n\n\n\n+2000 m<\/li>\n\n\n\n -800 m <\/li>\n\n\n\n + Rs 200<\/li>\n\n\n\n – Rs 200<\/li>\n<\/ol>\n\n\n\nQ 3. In each of the following pairs, which number is to the right of the other on the<\/strong><\/p>\n\n\n\nnumber line?<\/strong><\/p>\n\n\n\n\n2, 9 <\/strong><\/li>\n\n\n\n\u2013 3, \u2013 8 <\/strong>><\/li>\n\n\n\n0, \u2013 1<\/strong><\/li>\n<\/ol>\n\n\n\nAns. <\/strong>On the number line, all the numbers (whether positive or negative) are placed in an increasing order from left to right. The number to the right in each case is given below.<\/p>\n\n\n\n\nSince 2 < 9, 9 lies on the right side of 2 on the number line. <\/li>\n\n\n\n In this case, -3 > -8, so -3 lies on the right of -8 on the number line. <\/li>\n\n\n\n Again, 0 > -1, so 0 lies on the right of -1 on the number line.<\/li>\n<\/ol>\n\n\n\nQ 4. For the following statements, write True (T) or False (F). If the statement is false,<\/strong><\/p>\n\n\n\ncorrect the statement.<\/strong><\/p>\n\n\n\n\n\u2013 8 is to the right of \u2013 10 on a number line.<\/strong><\/li>\n\n\n\n\u2013 100 is to the right of \u2013 50 on a number line.<\/strong><\/li>\n\n\n\nThe smallest negative integer is \u2013 1.<\/strong><\/li>\n\n\n\n\u2013 26 is greater than \u2013 25<\/strong><\/li>\n<\/ol>\n\n\n\nAns. <\/strong>The answers in each case are given below.<\/p>\n\n\n\n\nTrue, because -8 > -10.<\/li>\n\n\n\n False, -100 < -50. So, -100 is to the left of -50 on the number line. <\/li>\n\n\n\n False, -1 is the greatest negative integer.<\/li>\n\n\n\n False, -26 < -25. <\/li>\n<\/ol>\n\n\n\nExercise 6.2<\/h3>\n\n\n\n Q 1. Find the sum of :<\/strong><\/p>\n\n\n\n\n137 and \u2013 354 <\/strong><\/li>\n\n\n\n\u2013 52 and 52<\/strong><\/li>\n\n\n\n\u2013 312, 39 and 192 <\/strong><\/li>\n\n\n\n\u2013 50, \u2013 200 and 300<\/strong><\/li>\n<\/ol>\n\n\n\nAns.<\/strong> Let us add the given integers below.<\/p>\n\n\n\n\n137 + (-354) = -217<\/li>\n\n\n\n -52 + 52 = 0<\/li>\n\n\n\n -312 + 39 + 192 = -312 + 231 = -81<\/li>\n\n\n\n -50 + (-200) + 300 = -50 -200 +300 = -250 + 300 = 50<\/li>\n<\/ol>\n\n\n\nQ 2. Add without using a number line.<\/strong><\/p>\n\n\n\n\n11+ (-7)<\/li>\n\n\n\n -13 + (+18)<\/li>\n\n\n\n -10 + (+19)<\/li>\n\n\n\n -250 + (+150)<\/li>\n\n\n\n -380 + (-270)<\/li>\n\n\n\n -217 + (-100)<\/li>\n<\/ol>\n\n\n\nAns. <\/strong>Let us add the given integers below:-<\/p>\n\n\n\n\n11 – 7= 4<\/li>\n\n\n\n -13 + 18= 5<\/li>\n\n\n\n -10 + 19= 9<\/li>\n\n\n\n -250 + 150= -100<\/li>\n\n\n\n -380 – 270= -650<\/li>\n\n\n\n -217 – 100= -317<\/li>\n<\/ol>\n\n\n\nQ 3. Find the sum<\/strong><\/p>\n\n\n\n\n-7 + (-9) + 4 + 16<\/li>\n\n\n\n 37 + (-2) + (-65) + (-8)<\/li>\n<\/ol>\n\n\n\nAns. <\/strong>1. -7 + (-9) + 4 = 16<\/p>\n\n\n\n-7 -9 +4 +16<\/p>\n\n\n\n
-16 + 4 +16<\/p>\n\n\n\n
-12 +16= 4<\/p>\n\n\n\n
<\/p>\n\n\n\n
2. 37 + (-2) + (-65) + (-8)<\/p>\n\n\n\n
37 – 2 – 65 – 8<\/p>\n\n\n\n
35 – 65 – 8<\/p>\n\n\n\n
-30-8= -38<\/p>\n\n\n\n
Exercise 6.3<\/h3>\n\n\n\n Q 1. Fill in the blanks with >, < or = sign.<\/strong><\/p>\n\n\n\n\n(\u2013 3) + (\u2013 6) ______ (\u2013 3) \u2013 (\u2013 6)<\/strong><\/li>\n\n\n\n(\u2013 21) \u2013 (\u2013 10) _____ (\u2013 31) + (\u2013 11)<\/strong><\/li>\n\n\n\n45 \u2013 (\u2013 11) ______ 57 + (\u2013 4)<\/strong><\/li>\n\n\n\n(\u2013 25) \u2013 (\u2013 42) _____ (\u2013 42) \u2013 (\u2013 25)<\/strong><\/li>\n<\/ol>\n\n\n\nAns. <\/strong>The answers are given below.<\/p>\n\n\n\n\n<<\/li>\n\n\n\n ><\/li>\n\n\n\n ><\/li>\n\n\n\n ><\/li>\n<\/ol>\n\n\n\nQ 2. Fill in the blanks.<\/strong><\/p>\n\n\n\n\n(\u2013 8) + _____ = 0<\/strong><\/li>\n\n\n\n13 + _____ = 0<\/strong><\/li>\n\n\n\n12 + (\u2013 12) = ____<\/strong><\/li>\n\n\n\n(\u2013 4) + ____ = \u2013 12<\/strong><\/li>\n\n\n\n____ \u2013 15 = \u2013 10<\/strong><\/li>\n<\/ol>\n\n\n\nAns:<\/strong> The answers are:<\/p>\n\n\n\n
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